NOTHING in present science has prepared us for this **ANSWER****!**

Issued: July 10th 2018.

ANSWER in htm: - *http://rbduncan.com/answer.htm*

Also ANSWER in Word: - *http://rbduncan.com/answer.doc*

And ANSWER in Adobe pdf: - *http://rbduncan.com/answer.pdf*

Dr. Milo Wolff's wave density formula in blue below Originally taken from Geoff's http://www.spaceandmotion.com/Cosmology but I see Geoff has now changed things.

"To examine this requirement we first make a quantitative assumption, similar to Mach's Principle, which establishes the density of space (ether or vacuum). Then we will examine the density formula seeking a means of interaction.** The Space Density assumption is:**

Assume that the mass (wave frequency) and propagation speed of an SR wave in space depends on the sum of all SR wave intensities in that space; a superposition of the intensities of waves from all particles inside the Hubble (H) Sphere of radius R = c/H, including the intensity of a particle's own waves.

mc^{2}= hw= k' SUM OF:{(AMP_{n})^{2 }x (1/r_{n}^{2})} (4)

In other words, the frequency w or mass m of a particle depends on the sum of amplitudes squared of all waves **AMP _{n}**, from the N particles in the universe, whose (

And then as you scroll further down:

"If an electron's own waves can create a denser region near its center, then the intensity I of those waves at some radius of non-linearity r_{o}, must be comparable to the intensity of waves from all other N particles in the Universe. This requirement is written:

Intensity I = AMP_{o}^{2}/r_{o}^{2 }= SUM { AMP_{n}^{2}/r_{n}^{2} } = N/V x INTEGRAL OF:{ AMP_{o}/r_{o}}^{2} 4 pi r ^{2}dr

where V is the volume inside the Hubble Sphere and R its radius. The integral, from r = 0 to R = cT = c/H, extends over a sphere whose expanding radius R depends on the age T of the particle. Thus T is the maximum range of the particle's spherical waves. This reduces to

r_{o}^{2} = R ^{2}/3N (5)

Inserting values from astronomy measures, R = 10^{26} meters and N = 10^{80} particles, the critical radius r_{o} equals 6 x 10^{-15 }meter. If the assumption is right, this should approximate the classical radius r_{c} = e^{2} /mc^{2}of an electron, which is 2.8 x 10^{-15} meters. The two values almost match, so the prediction is verified. Apparently dense wave centers do exist, and

e^{2} / mc^{2} = R / SQUARE ROOT OF: {3N} (6)

Equation (5) is a relation between the size r_{o} of an electron and the size R of the Hubble Universe.

**You must understand this if you want to understand the scalar wave aspect of it all.**

*Fitzpatrick's First Book* (FREE)

This link is in htm.*Over 4 Decades of Daniel P. Fitzpatrick's Books, Papers and Thoughts*

Over 4 Decades of Fitzpatrick's Books, Papers & Thoughts in PDF*http://www.amperefitz.com/4.decades.pdf*